In this blog post, we’ll discuss how to determine if an array is a palindrome using Java programming language. A palindrome is a string or an array that remains the same even when reversed. For example, [“a”, “b”, “c”, “b”, “a”] is a palindrome array.

To check if an array is a palindrome, we can use the following steps:

Step 1: Initialize Pointers

We’ll initialize two pointers, one pointing to the start of the array (let’s call it start) and the other pointing to the end of the array (let’s call it end).

int start = 0;
int end = array.length - 1;

Step 2: Compare Elements

We’ll compare the elements at start and end pointers iteratively while moving the start pointer towards the end and the end pointer towards the start.

while (start < end) {
    // Compare elements
    if (!array[start].equals(array[end])) {
        // Array is not a palindrome
        return false;
    }

    // Move pointers
    start++;
    end--;
}

Step 3: Array is Palindrome

If the loop completes without finding any differences between the elements, the array is a palindrome.

return true;

Full Code Example

Here’s a full example demonstrating the implementation of checking if an array is a palindrome in Java:

public class PalindromeChecker {
    public static boolean isPalindrome(String[] array) {
        int start = 0;
        int end = array.length - 1;

        while (start < end) {
            if (!array[start].equals(array[end])) {
                return false;
            }

            start++;
            end--;
        }

        return true;
    }

    public static void main(String[] args) {
        String[] palindromeArray = {"a", "b", "c", "b", "a"};
        String[] nonPalindromeArray = {"a", "b", "c", "d", "e"};

        System.out.println(isPalindrome(palindromeArray)); // Output: true
        System.out.println(isPalindrome(nonPalindromeArray)); // Output: false
    }
}

Conclusion

By following the steps outlined in this blog post and using the provided code example, you can easily check if an array is a palindrome in Java. This technique can be useful in various scenarios where you need to determine the symmetry or uniqueness of arrays.

#tech #Java